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5x^2-50x+625=680
We move all terms to the left:
5x^2-50x+625-(680)=0
We add all the numbers together, and all the variables
5x^2-50x-55=0
a = 5; b = -50; c = -55;
Δ = b2-4ac
Δ = -502-4·5·(-55)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-60}{2*5}=\frac{-10}{10} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+60}{2*5}=\frac{110}{10} =11 $
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